3 April, 19:27
A company's board of directors wants to form a committee of 3 of its members. There are 4 members to choose from. How many different committees of 3 members could possibly be formed?
3 April, 21:18
There are 4 board members and 3 committee members. You can solve this using combinations:
4C3 = 4! / (3! (4-3) !) = 4! / (3!1!) = 4
You can also solve this by recognizing that since there is one fewer committee spot than there are board members, there will be one possible committee excluding each of the 4 board members.
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» A company's board of directors wants to form a committee of 3 of its members. There are 4 members to choose from. How many different committees of 3 members could possibly be formed?