Factor completely: 16x4 - 1 A. (4x + 1) (4x - 1) B. (4x2 + 1) (4x2 - 1) C. (2x + 1) 3 (2x - 1) D. (4x2 + 1) (2x + 1) (2x - 1)

Question

Miriam Riddle

Mathematics

11 April, 23:54

Factor completely: 16x4 - 1 A. (4x + 1) (4x - 1) B. (4x2 + 1) (4x2 - 1) C. (2x + 1) 3 (2x - 1) D. (4x2 + 1) (2x + 1) (2x - 1)

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Jadiel · Answer 1

Remember a^2-b^2 = (a-b) (a+b) 16=4^2 x^4 = (x^2) ^2 so 16x^4-1 = (4x^2) ^2 - (1) ^2 = (4x^2-1) (4x^2+1) and the 4x^2-1 can be further factored (2x) ^2 - (1) ^2 = (2x-1) (2x+1) factoref rom is (4x^2+1) (2x+1) (2x-1) D is answer