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Itzel Cole
Mathematics
14 June, 01:46
The sum of foir consecutive even integers is - 28
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Marcos Erickson
14 June, 02:00
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If we call the first integer n, the next three integers must be one multiple of 2 away each, giving us the integers n, n + 2, n + 4, and n + 6. We're told these sum to - 28, so we can put these integers into the equation
n + (n + 2) + (n + 4) + (n + 6) = - 28
Solving for n:
n + n + 2 + n + 4 + n + 6 = 28
4n + 12 = - 28 (collecting like terms)
n + 3 = - 7 (diving both sides by 4)
n = - 10
So our four integers are - 10, - 8, - 6, and - 4.
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