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1 June, 20:16

The line width for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometers what is the probability that a line width is greater than 0.62 micrometer?

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  1. 1 June, 20:29
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    To solve the question we first calculate the z-score:

    z = (x-μ) / σ

    where:

    μ-mean

    σ-standard deviation

    thus from the information given we shall have:

    z = (0.62-0.5) / 0.05

    z=2.4

    Thus

    P (x>0.62) = 1-P (x<0.62)

    =1-P (z=2.4) = 1-0.9918

    =0.0082
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