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21 April, 12:18

Given the functions k (x) = 2x^2 - 7 and p (x) = x - 4, find (k ∘ p) (x).

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  1. 21 April, 12:54
    0
    = 2x^3-8x^2-7x+28

    Step-by-step explanation:

    Multiply k (x) by p (x):

    (2x^2-7) (x-4) = 2x^3-8x^2-7x+28

    (don't forget to add the exponent when you multiply it by x: 2x^2*x = 2x^3)
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