Given the functions k (x) = 2x^2 - 7 and p (x) = x - 4, find (k ∘ p) (x).

= 2x^3-8x^2-7x+28

Step-by-step explanation:

Multiply k (x) by p (x):

(2x^2-7) (x-4) = 2x^3-8x^2-7x+28

(don't forget to add the exponent when you multiply it by x: 2x^2*x = 2x^3)