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14 March, 23:31

For this question, Determine if the equation is always, sometimes, or never true. If the equation is sometimes true, determine the numbers that make it true.

The equation is: 6y + 5 = 4y + 5 and - 2 (6 - 10n) = 10 (2n - 6)

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  1. 14 March, 23:56
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    If I've understood correctly,

    First eq'n:

    True only when y = 0

    [simply rearrange the eq'n to solve for y]

    Second eq'n:

    Never true

    [when you expand and simplify you will get some two different integers equated to each other which is incorrect; the integers will vary depending on how and how much simplifying you do]
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