Pythagorean triples are given by these formulas:

(x^2 - y^2, 2xy, x^2 + y^2)

The length of one leg of a right triangle is 28. The lengths of the other sides are odd numbers. Which of these numbers could be the length of the hypotenuse? Choose all that apply.

45

53

65

195

197

Question

Chana Griffith

Mathematics

18 September, 22:37

Pythagorean triples are given by these formulas:

(x^2 - y^2, 2xy, x^2 + y^2)

The length of one leg of a right triangle is 28. The lengths of the other sides are odd numbers. Which of these numbers could be the length of the hypotenuse? Choose all that apply.

45

53

65

195

197

+2

Answers (1)

Know the Answer?

Aria Donaldson · Answer 1

One could be 53 because 53^2 = 28^2 + 45^2

45 and 65 are not possibe because the other leg isnt a whole number. Same or 195

197 could be because 197^2 = 195^2 + 28^2

Pythagorean triples are given by these formulas:(x^2 - y^2, 2xy, x^2 + y^2)The length of one leg of a right triangle is 28. The lengths of the other sides are odd numbers. Which of these numbers could be the length of the hypotenuse? Choose all that apply.455365195197

Pythagorean triples are given by these formulas:

(x^2 - y^2, 2xy, x^2 + y^2)

The length of one leg of a right triangle is 28. The lengths of the other sides are odd numbers. Which of these numbers could be the length of the hypotenuse? Choose all that apply.

45

53

65

195

197