Solve (x+2) (2x+3) = 6

{-2,3/2}

{-7/2,0}

{0}

Question

Nathaniel Shah

Mathematics

21 December, 08:13

Solve (x+2) (2x+3) = 6

{-2,3/2}

{-7/2,0}

{0}

+4

Answers (1)

Know the Answer?

Cassius Hatfield · Answer 1

{-7/2,0}

Step-by-step explanation:

(x+2) (2x+3) = 6

FOIL

first 2x^2

outer 3x

inner 4x

last 6

2x^2 + 7x+6

2x^2 + 7x+6 = 6

Subtract 6 from each side

2x^2 + 7x+6-6 = 6-6

2x^2 + 7x = 0

Factor out x

x (2x+7) = 0

Using the zero product property

x=0 2x+7 = 0

x=0 2x=-7

x=0 x = - 7/2

Solve (x+2) (2x+3) = 6{-2,3/2}{-7/2,0}{0}

Solve (x+2) (2x+3) = 6

{-2,3/2}

{-7/2,0}

{0}