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20 September, 23:32

What is the 7th term of the geometric sequence where a1 = 128 and a3 = 8?

A.) 0.03125

B.) 0.0625

C.) 0.125

D.) 0.15625

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  1. 20 September, 23:58
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    An = ar^ (n-1)

    a3 = 128r^ (3 - 1) = 128r^2

    128r^2 = 8

    r^2 = 8/128 = 1/16

    r = sqrt (1/16) = 1/4

    a7 = 128r^ (7 - 1) = 128r^6 = 128 (1/4) ^6 = 128 (1/4,096) = 0.03125
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