Ask Question
23 May, 12:54

At a concession stand, three hot dog (s) and two hamburger (s) cost $6.50 ; two hot dog (s) and three hamburger (s) cost $7.25. Find the cost of one hot dog and the cost of one hamburger.

+5
Answers (1)
  1. 23 May, 13:14
    0
    The cost of one hot dog is $1 and the cost of one hamburger is $1.75

    Step-by-step explanation:

    We are going to make 2 equations with which the problem tells us

    h = hamburger cost

    d = hot dog cost

    3d + 2h = $6.50

    3h + 2d = $7.25

    we clear the h in the first equation

    3d + 2h = $6.50

    2h = 6.50 - 3d

    h = (6.50 - 3d) / 2

    h = (6.50 - 3d) / 2

    h = (3.25 - 3/2 d)

    we replace the value of h in the second equation by (3.25 - 3/2 d)

    3h + 2d = $7.25

    3 (3.25 - 3/2 d) + 2d = $7.25

    9.75 - 9/2 d + 2d = 7.25

    - 9/2 d + 2d = 7.25 - 9.75

    -5/2 d = - 2.5

    d = - 2.5 / (-5/2)

    d = 1

    we replace the value obtained from d in the first equation

    h = (3.25 - 3/2 d)

    h = (3.25 - 3/2 * (1))

    h = 3.25 - 1.5

    h = 1.75

    The cost of one hot dog is $1 and the cost of one hamburger is $1.75
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “At a concession stand, three hot dog (s) and two hamburger (s) cost $6.50 ; two hot dog (s) and three hamburger (s) cost $7.25. Find the ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers