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15 June, 02:11

Find the vertex form of the following equation by completing the square.

y = 3x^2+6x+8

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  1. 15 June, 02:19
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    Y = 3x^2 + 6x + 8

    y = 3 (x^2 + 2x + 1) + 5

    y = 3 (x+1) ^2 + 5

    y - 5 = 3 (x+) ^2
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