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Atticus
Mathematics
27 November, 19:38
Verify the identity secx-secx sin^2x=cosx
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Anton Wilkerson
27 November, 20:03
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Hello:
* secx = 1/cosx
cos²x+sin²x = 1
**sin²x = 1-cos²x
by (*):
secx-secx sin²x = (1/cosx) - (1/cosx) sin²x
= (1/cosx) (1 - sin²x) ... factory : (1/cosx)
by (**)
secx-secx sin²x = (1/cosx) cos²x
secx-secx sin²x = cosx ... (simplify by : cosx)
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