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3 July, 05:52

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 6 kg, the acceleration of the object is 7 / ms2. If the same force acts upon another object whose mass is 14 kg, what is this object's acceleration?

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  1. 3 July, 06:02
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    Answer: a = 3 m/s^2

    Step-by-step explanation:

    Let the acceleration of the object be represented by a

    Let the constant force acting on the object be represented by k

    Let the mass of the object represented by m

    When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. This means that

    a = k/m

    When a certain constant force acts upon an object with mass 6 kg, the acceleration of the object is 7 / ms2. It means that when a = 7, m = 6. We would find k. Therefore

    7 = k/6

    k = 7*6 = 42

    The expression becomes

    a = 42/m

    If the same force acts upon another object whose mass is 14 kg, it means that m = 14, then

    a = 42/14 = 3
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