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20 February, 04:54

If g (x) = 4x2-16 were shifter 5 units to the right and 2 down, what would the new equation be?

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  1. 20 February, 05:05
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    G (x) = 4x^2-16

    To shift to the right we have to subtract from the value of x, in this case by 5 units ...

    h (x) = 4 (x-5) ^2-16

    h (x) = 4 (x^2-10x+25) - 16

    h (x) = 4x^2-40x+100-16

    h (x) = 4x^2-40x+84

    Now to shift the function downwards by 2 units we must subtract the constant 2 from h (x)

    h (x) = 4x^2-40x+84-2

    h (x) = 4x^2-40x+82
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