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2 May, 02:43

The vertices of a feasible region are (14, 2), (0, 9), (6, 8), and (10, 3). What is the maximum value of P if P = 180x + 250y?

2,940

3,020

3,080

3,250

+2
Answers (1)
  1. 2 May, 02:50
    0
    We simply use guess-and-check. For (14, 2), P=180*14+2*250=3020. For (0, 9), it equals 9*250=2250. For (6, 8) it equals 6*180+8*250=3080. Finally, for (10, 3), it equals 10*180+3*250=2550. The greatest among these is 3080.
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