Ask Question
23 April, 13:15

What is the ratio of the area of the inner square to the area of the outer square?

(a-b) ²+b²/a²

a²-b²/a²

(a-b) ² / (a+b) ²

(ab) ² / (a+b) ²

+3
Answers (1)
  1. 23 April, 13:18
    0
    The answer is

    (a-b) ²+b²/a²

    proof

    if A is the area of the

    inner squared, so A = c², and c² = (a-b) ²+b²

    so the side of the outer must be a-b + b=a, its area is a²
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the ratio of the area of the inner square to the area of the outer square? (a-b) ²+b²/a² a²-b²/a² (a-b) ² / (a+b) ² (ab) ² / (a+b) ² ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers