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28 January, 21:32

From the top of a 100 meter bulding the angle of elevation to the top of another building on the opposite side of the street is 25 degrees and angle of depression to the foot of the building is 40 degrees. find the height of the opposite building

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  1. 28 January, 21:35
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    If the opposite building is x m higher than the 100m builder and y is distance between the 2 buildings we have the equations:-

    tan 25 = x / y

    tan 40 = 100/y

    y = 100 / tan 40 = 119.18

    substituting in first equation

    tan 25 = x / 119.18

    x = 119.18 * tan25 = 55.57 m

    So the height of the opposite building = 100 + 55.57 = 155.57 m answer
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