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3 November, 12:57

For 'z_1 = 9"cis" (5pi) / (6) ' and 'z_2 = 3"cis" (pi) / (3) ', find ' (z1) / (z2) ' in rectangular form.

a) - 3

b) 3

c) - 3i

d) 3i

+3
Answers (1)
  1. 3 November, 13:00
    0
    option D is correct, i. e. 3i

    Step-by-step explanation:

    Given are the complex number as Z₁ = 9 cis (5π/6) and Z₂ = 3 cis (π/3)

    So magnitudes are r₁ = 9, and r₂ = 3

    And arguments are ∅₁ = 5π/6, and ∅₂ = π/3

    We know the formula for division of complex number is given as follows:-

    If Z₁ = r₁ cis (∅₁) and Z₂ = r₂ cis (∅₂)

    Then |Z₁ / Z₂| = (r₁/r₂) cis (∅₁ - ∅₂)

    |Z₁ / Z₂| = (9/3) cis (5π/6 - π/3)

    |Z₁ / Z₂| = 3 cis (5π/6 - 2π/6)

    |Z₁ / Z₂| = 3 cis (3π/6)

    |Z₁ / Z₂| = 3 cis (π/2)

    |Z₁ / Z₂| = 3 cos (π/2) + 3i sin (π/2)

    |Z₁ / Z₂| = 3 * (0) + 3i * (1)

    |Z₁ / Z₂| = 0 + 3i

    |Z₁ / Z₂| = 3i

    Hence, option D is correct, i. e. 3i
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