a dart board has 10 equally sized slices numbered from 1-10. some are grey and some are white. the slices numbered 1,2,3,4,5,6,8,9 and 10 are grey. the slice number 7 is white. a dart is tossed and lands on a slice at random. let X be the event that the dart lands on a grey slice, and let P (X) be the probability of x. let not X be the event that the dart lands on a slice that is not grey, and let P (not X) be the probability of not X.

Question

Ethen Stewart

Mathematics

13 April, 17:46

a dart board has 10 equally sized slices numbered from 1-10. some are grey and some are white. the slices numbered 1,2,3,4,5,6,8,9 and 10 are grey. the slice number 7 is white. a dart is tossed and lands on a slice at random. let X be the event that the dart lands on a grey slice, and let P (X) be the probability of x. let not X be the event that the dart lands on a slice that is not grey, and let P (not X) be the probability of not X.

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Baird · Answer 1

We have 10 sections, we can assume that the probability of hitting each of one of them is the same.

we have 9 grey slices and 1 white slice, then the probability of landing in a grey slice is equal to the number of grey slices divided by the total number of slices:

P (X) = 9/10 = 0.90

The probability of not landing in a grey slice is equal to the probability of landing in the white slice, this is:

P (not X) = 1/10 = 0.10

Also, when you have only two events, you can calculate this as:

P (not X) = 1 - P (X) = 1 - 0.90 = 0.10