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7 January, 09:25

Factor completely 16a^3b^7 + 2a^6 b4 - 22a ^4 b^5.

2 (8a3b7 + a6b4 - 11a4b5)

2a3b4 (8b3 + a3 - 11ab)

a3b4 (16b3 + 2a3 - 22ab)

8b3 + a3 - 11ab

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Answers (1)
  1. 7 January, 09:29
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    Factor out 2a^3 from the epression

    so it would become 2a^3b (8b^6 + a^3 * 4 - 11ab^4)

    then you would use the communitive property to re order the terms

    so your answer is 2a^3b * (8b^6 + 4a^3 - 11ab^4)
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