How can 1/4x - 3 = 1/2x + 8 be set up as a system of equations?

Equation (1) y=1/4x-3

Equation (2) y=1/2x+8

For this case, the first thing you should do is define the following variables:

y = 1 / 4x - 3

y = 1 / 2x + 8

We now rewrite the equations:

4y = x - 12

2y = x + 16

We place the variables on the left side of the equality:

4y-x = - 12

2y-x = + 16

From where we obtain the system of equations sought.

Answer:

The system of equations is:

4y-x = - 12

2y-x = + 16