Ask Question
26 September, 17:36

A local hamburger shop sold a combined total of 763 hamburgers and cheeseburgers on Saturday. There were 63 more cheeseburgers sold than hamburgers. How many hamburgers were sold on Saturday?

+5
Answers (1)
  1. 26 September, 17:38
    0
    In order to solve this we'll start by assigning variables to hamburgers and cheeseburgers, since these are what we're trying to find. Lets say x = hamburgers and y = cheeseburgers. So we know two things, we know that x+y = 763 (hamburgers plus cheeseburgers sold equals 763, and we know that y = x+63 (cheeseburgers sold equals 63 more than hamburgers sold). Now we have a system of equations. This can be solved most easily by rearranging each equation to each y, and then set them equal to each other:

    x+y=763 - > y=763-x, and we already have y=x+63. Set them equal to each other:

    x+63 = 763-x (add x to both sides) - > 2x+63 = 763 (subtract 63 from both sides) - > 2x = 700 (divide both sides by 2) x = 350. So we solved for x, which is hamburgers sold, which is what the question asks for, so your answer is 350 hamburgers were sold on Saturday
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A local hamburger shop sold a combined total of 763 hamburgers and cheeseburgers on Saturday. There were 63 more cheeseburgers sold than ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers