What are the explicit equation and domain for an arithmetic sequence with a first term of 6 and a second term of 2?

an = 6 - 2 (n - 1); all integers where n ≥ 1

an = 6 - 2 (n - 1); all integers where n ≥ 0

an = 6 - 4 (n - 1); all integers where n ≥ 0

an = 6 - 4 (n - 1); all integers where n ≥ 1

Question

Brandon Schroeder

Mathematics

30 March, 10:00

What are the explicit equation and domain for an arithmetic sequence with a first term of 6 and a second term of 2?

an = 6 - 2 (n - 1); all integers where n ≥ 1

an = 6 - 2 (n - 1); all integers where n ≥ 0

an = 6 - 4 (n - 1); all integers where n ≥ 0

an = 6 - 4 (n - 1); all integers where n ≥ 1

+5

Answers (1)

Know the Answer?

Perla Green · Answer 1

Hello:

the answer is:

an = 6 - 4 (n - 1); all integers where n ≥ 1

because:

if n=1 a1 = 6-4 (1-1) = 6

if n=2 a2 = 6-4 (2-1) = 2

the common difference is : a2-a1 = 2-6=-4

What are the explicit equation and domain for an arithmetic sequence with a first term of 6 and a second term of 2?an = 6 - 2 (n - 1); all integers where n ≥ 1an = 6 - 2 (n - 1); all integers where n ≥ 0an = 6 - 4 (n - 1); all integers where n ≥ 0an = 6 - 4 (n - 1); all integers where n ≥ 1