Use technology or a z-distribution table to find the indicated area.

The number of huckleberries picked during a huckleberry contest are normally distributed with a mean of 300 and a standard deviation of 100. Jill picked 300 huckleberries in the contest.

What percent of huckleberry pickers picked less than Jill?

10%

25%

50%

75%

Question

Elian

Mathematics

22 July, 01:52

Use technology or a z-distribution table to find the indicated area.

The number of huckleberries picked during a huckleberry contest are normally distributed with a mean of 300 and a standard deviation of 100. Jill picked 300 huckleberries in the contest.

What percent of huckleberry pickers picked less than Jill?

10%

25%

50%

75%

+5

Answers (1)

Know the Answer?

Alyson Burke · Answer 1

Jill picked 300 huckleberries in the contest and a mean value is also 300.

The normal distribution has symmetry about the center; 50 % of values is less than a mean and 50 % is greater than a mean.

Answer:

The percent of huckleberry pickers who picked less than Jill is C) 50 %.