A projectile is launched upward with a velocity of 64 feet per second from the top of a 45-foot platform. What is the maximum height attained by the projectile?

height function

Question

Samantha Kaufman

Mathematics

30 March, 03:12

A projectile is launched upward with a velocity of 64 feet per second from the top of a 45-foot platform. What is the maximum height attained by the projectile?

height function

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Answers (1)

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Carson Ochoa · Answer 1

Step-by-step explanation:

xf=xo+vot+1/2 g t^2

xo=45 f vo=64 f/s g = - 32.2 ft/s^2

h (t) = - 16.1 t^2 + 64t + 45 parobola max will be at t = - b/2a

-64 / (2 (-16.1) = 1.987 sec = tmax

-16.1 (1.987^2) + 64 (1.987) + 45 = 108.6 ft

A projectile is launched upward with a velocity of 64 feet per second from the top of a 45-foot platform. What is the maximum height attained by the projectile?height function

A projectile is launched upward with a velocity of 64 feet per second from the top of a 45-foot platform. What is the maximum height attained by the projectile?

height function