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17 July, 09:52

Factor completely 2x^3y^4-8x^2y^3+6xy^2

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  1. 17 July, 11:07
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    2 x y^2 (x y - 1) (x y - 3)

    Step-by-step explanation:

    2x^3y^4-8x^2y^3+6xy^2

    each term contains 2xy^2 so factor that out

    2xy^2 (x^2y^2 - 4xy+3)

    then lets factor the inside

    what terms multiply together to give us + 3 and add to - 4

    -3 * - 1 = 3 - 3+-1 = -4

    2 x y^2 (x y - 1) (x y - 3)
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