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Emery Hancock
Mathematics
7 February, 15:12
Factor completely 2x^3y^4-8x^2y^3+6xy^2
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Brenden Wagner
7 February, 15:33
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2 x y^2 (x y - 1) (x y - 3)
Step-by-step explanation:
2x^3y^4-8x^2y^3+6xy^2
each term contains 2xy^2 so factor that out
2xy^2 (x^2y^2 - 4xy+3)
then lets factor the inside
what terms multiply together to give us + 3 and add to - 4
-3 * - 1 = 3 - 3+-1 = -4
2 x y^2 (x y - 1) (x y - 3)
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