Find two arithmetic means between 6 and 30

Answer

14.22

Step-by-step explanation:

Let d be the common difference betwen consecutive terms of the arithmetic sequence.

Two arithmetic means required are 6 + d and 6 + 2d, where 6 + 3d = 30.

6 + 3d = 30

3d = 24

d = 8.

The two means required are 6 + 8 = 14, and 6 + 2 * 8 = 22.