Peg and pat are sharing 64 crayons Pat has 10 more crayons than peg how many crayons does each girl have

Number of crayons have Peg: x=?

Number of crayons have Pat: y=?

Peg and Pat are sharing 64 crayons:

(1) x+y=64

Pat has 10 more crayons than Peg:

(2) y=x+10

We have a system of 2 equations and 2 unkowns. Using the method of substitution:

Replacing (2) y=x+10 in equation (1):

(1) x+y=64

x + (x+10) = 64

x+x+10=64

2x+10=64

Solving for x:

2x+10-10=64-10

2x=54

2x/2=54/2

x=27

Replacing x=10 in equation (2)

(2) y=x+10

y=27+10

y=37

Answer:

Peg has 27 crayons

Pat has 37 crayons