Ask Question
28 March, 15:34

Patrick, Paulo, and Joseph divided 68 oranges. Patrick got two oranges less than Paulo and Paulo got twice as much as Joseph. How many oranges did Joseph get?

+4
Answers (1)
  1. 28 March, 15:45
    0
    Let's say patrick=a, paulo=b and joseph=c:

    (1) a+b+c=68

    (2) a+2=b

    (3) b=2c

    substituting (2) in (1) gives:

    (4) 2a + c = 66 = > a = 33 - c/2

    (3) in (2) gives:

    (5) a+2=2c

    (4) in (5):

    33 - c/2 + 2 = 2c = > 35 = 2.5c = > c=14

    Joseph got 14 oranges!
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Patrick, Paulo, and Joseph divided 68 oranges. Patrick got two oranges less than Paulo and Paulo got twice as much as Joseph. How many ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers