One number is 2 more than 3 times another. their sum is 22. find the numbers

1st number = x, 2nd number = y

Translating the question mathematically it becomes:

x-2 = 3y, or to make it easier: x = 3y+2, x+y = 22

Thus:

(3y + 2) + y = 22

4y + 2 = 22

Move the 2 on the other side, changing its sign to negative:

4y = 22 - 2

4y = 20

Divide by 4, to obtain only y:

4y : 4 = 20 : 4

y = 5

To obtain x:

x = (3*5) + 2 = 15+2 = 17

Verify it: 17+5=22