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18 March, 08:04

How do I express this as a quadratic in standard form

(-a+1) (5a+6)

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Answers (2)
  1. 18 March, 08:17
    0
    Standard form is ax + by = c

    (-a+1) (5a+6) distribute.

    -a times 5a = - 5a^2, - a times 6 = - 6a

    1 times 5a = 5a, 1 times 6 = 6

    Then write it out properly.

    -5a^2 - 6a + 5a + 6 = 0

    Then combine like terms.

    -6a + 5a = - a

    So the answer is - 5a^2 - a + 6
  2. 18 March, 08:24
    0
    (1 - a) • (5a + 6) is the answer
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