In a certain normal distribution of scores, the mean is 40 and the standard deviation is 3. Find the Z-score corresponding to a score

of 54.

a. 4.67

c. 4.67

b. 18.0

d. 13.33

choice a.) 4.67

Step-by-step explanation:

We have a Normal curve

mean u = 40

standard deviation s = 3

we can the z-score for x = 54

P (X > 54) = probability corresponding to the z-score

P (Z > (54 - 40) / 3) = P (Z > 14/3) = P (Z > 4.667)

The Z-score: Z > (54 - 40) / 3 = 4.667

but the Probability is close to 0 about 0.000003