The Math Club sold roses and tulips this year for valentines day. The number of roses sold was 8 more than 4 times the number of tulips sold. Tulips were sold for $2 each and roses for $5 each. The club made $414.00. How many roses were sold?

Question

Dalia Rosales

Mathematics

16 September, 04:04

The Math Club sold roses and tulips this year for valentines day. The number of roses sold was 8 more than 4 times the number of tulips sold. Tulips were sold for $2 each and roses for $5 each. The club made $414.00. How many roses were sold?

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Answers (1)

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Mariyah Barry · Answer 1

In this question there are several information's of immense importance. They can be used to get the required answer. It is given that the Math Club sold 8 more roses than 4 times the number of tulip[s. The cost of each Tulip was $2 and the cost of each rose was $5. Total amount gained is $414.

Now

Let us assume the number of roses sold = x

Number of Tulips sold = y

Then

x = 8 + 4y

5x + 2y = 414

Now if we replace the value of x from the first equation to the second equation we get:

5x + 2y = 414

5 (8 + 4y) + 2y = 414

40 + 20y + 2y = 414

22y = 414 - 40

22y = 374

y = 374/22

= 17

Now putting the value of y in the first equation we get:

x = 8 + 4y

= 8 + 4 (17)

= 8 + 68

= 76

So the Math Club sold 76 roses and 17 tulips.