Use substitution to solve the system:

x=3y-2

5x+4y=28

We can rewrite what x is in terms of y (since we know it from the first equation)

I will substitute in the 2nd equation

5 (3y-2) + 4y = 28

15y - 10 + 4y = 28

Combine like terms

19y - 10 = 28

Move the 10 over by adding it to both sides

19y - 10 + 10 = 28 + 10

19y = 38 now divide both sides by 19

19y = 38

19 19 and we get that y = 2

Now substitute in either equation - i choose the first

x = 3 (2) - 2 x = 6-2 = 4 so x = 4

This works in the 2nd equation too. Try it.

Final answer x = 4 y = 2