Ask Question
14 July, 05:09

Solve the following system by substitution.

X+2y=14

6x+3y=21

+5
Answers (1)
  1. 14 July, 05:13
    0
    Step-by-step explanation:

    x + 2y = 14 ... (1)

    6x + 3y = 21 ... (2)

    Solve for x in equation 1

    When x + 2y = 14

    Therefore x = 14 - 2y ... (3)

    Now put equation 3 in equation 2 and solve

    6x + 3y = 21 ... (2)

    6 (14 - 2y) + 3y = 21

    Open the bracket and resolve

    84 - 12y + 3y = 21

    -9y + 84 = 21

    Now collect the like terms

    -9y + 84 = 21

    -9y = 21 - 84

    -9y = - 63

    Divide through by - 9 to get y

    y = - 63/-9

    y = 7

    Substitute for y in equation (3) to x

    x = 14 - 2y ... (3)

    So, x = 14 - 2 (7)

    x = 14 - 14

    x = 0.

    Therefore x = 0 and y = 7

    Check: From equation (1)

    x + 2y = 14

    Now, put x = 0 and y = - 2

    Therefore, 0 + 2 (7) = 14

    0 + 14 = 14
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Solve the following system by substitution. X+2y=14 6x+3y=21 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers