4. A circle is centered at (-8, - 13) and has a radius of 13. What is the equation of the circle? * (x + 8) ² + (y + 13) ² = 169 (x + 13) ² + (y + 8) ² = 169 (x - 8) ² + (y - 13) ² = 64 (x - 8) ² + (y - 13) ² = 169

Question

Kamryn

Mathematics

3 August, 06:56

4. A circle is centered at (-8, - 13) and has a radius of 13. What is the equation of the circle? * (x + 8) ² + (y + 13) ² = 169 (x + 13) ² + (y + 8) ² = 169 (x - 8) ² + (y - 13) ² = 64 (x - 8) ² + (y - 13) ² = 169

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Answers (1)

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Edwin · Answer 1

(x + 8) ^2 + (y + 13) ^2 = 13^2

Step-by-step explanation:

Write out (x - h) ^2 + (y - k) ^2 = r^2. Recognizing that the center is at

(h, k), with h = - 8 and k = - 13, and that the radius is 13, we get:

(x + 8) ^2 + (y + 13) ^2 = 13^2