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22 June, 00:05

What is the solution to 2log (x) =

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  1. 22 June, 00:21
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    you can't really solve for it unless it equals something or there's a value for x. Assuming this logarithm is base 10 ... you can set it equal to y and simplify it.

    2log (x) = log (x^2)

    log (x^2) = y

    x^2 = 10^y
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