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21 February, 03:38

Find the number of real solutions of the equation x^2+10x+35=0 using the discriminant: (b^2-4ac)

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  1. 21 February, 03:40
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    Answer: No real roots or solutions

    Step-by-step explanation:

    X^2+10x+35=0 using this equation you can tell that a=1, b=10, and c=35. Using the numbers for the formula,

    b^2 - 4ac, it will look like this ... 10^2-4 (1) (35). Next step is the exponent. It will look like this now, 100-4 (1) (35), the next step is to multiply. 100-140 = - 40. When the discriminant is negative, there are no real roots, or solutions.
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