London Harper

Mathematics

12 January, 07:54

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f (x) = 4x^2 + 3x + 4, [-1, 1]

No, f is continuous on [-1, 1] but not differentiable on (-1, 1).

No, f is not continuous on [-1, 1].

Yes, f is continuous on [-1, 1] and differentiable on (-1, 1) since polynomials are continuous and differentiable on.

There is not enough information to verify if this function satisfies the Mean Value Theorem.

Yes, it does not matter if f is continuous or differentiable; every function satisfies the Mean Value Theorem.