Twice the difference of a number n and seven is equal to four less than the product of five and the number n. What is that value of n?

N=-10/3n = - 1n = 1n = 10/7

Question

Nolan

Mathematics

9 December, 20:28

Twice the difference of a number n and seven is equal to four less than the product of five and the number n. What is that value of n?

N=-10/3n = - 1n = 1n = 10/7

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Answers (1)

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Mcpherson · Answer 1

n=-10/3

Step-by-step explanation:

"Twice the difference of a number n and seven is equal to four less than the product of five and the number n" translates into 2 (n-7) = 5n - 4. To solve, isolate the variable n.

2 (n-7) = 5n - 4

2n - 14 = 5n - 4

2n - 10 = 5n

-10 = 3n

-10/3 = n

Twice the difference of a number n and seven is equal to four less than the product of five and the number n. What is that value of n?N=-10/3n = - 1n = 1n = 10/7

Twice the difference of a number n and seven is equal to four less than the product of five and the number n. What is that value of n?

N=-10/3n = - 1n = 1n = 10/7