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26 January, 11:33

in the equation x+3y=6, suppose the x-intercept was at (m, 0) and the y - intercept was at the ordered pair (0, n). what is the value of m+n

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  1. 26 January, 11:52
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    8

    Step-by-step explanation:

    The x intercept is when y = 0

    x + 3 (0) = 6

    x = 6

    So (6,0) and m = 6

    the y intercept is when x = 0

    0 + 3y = 6 Divide by 3

    y = 6/3

    y = 2

    the y intercept is (0,2) and n = 2

    Answer

    m + n = 6 + 2 = 8
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