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29 December, 22:42

F (a) = 2a^2-16a+32

For which 'a' is this equation 0?

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  1. 29 December, 22:54
    0
    If xy=0 assume that at leas 1 is zero

    set it to zero

    0=2a^2-16a+32

    undistribute 2

    0=2 (a^2-8a+16)

    2*0=0 so assume

    a^2-8a+16=0

    factor

    (a-4) (a-4) = 0

    set to zero

    a-4=0

    a=4

    when a=4, equation equals zero
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