What is the least number that has 4 odd factors that are all the same? Each factor is greater than 1 and can have only 1 itself as factors

1,2,3 is prime 4 is not prime is i would say four sine its all the same it's kind of like 1x1x1x1 = 1

I'm not quite sure what you mean.

the factors can't be 1.

the factors have to be odd.

they have to be the same.

offhand i would say 3*3*3*3 would be equal to 9*9 = 81.

the number 81 has 4 odd factors that are all the same.

can't be 1 because 1 doesn't counts as a factor.

a prime number has 2 factors.

1 and itself.

every number has a factor of 1 and itself.