What is the equation of a circle with center (8,6) and radius 5?

O A. (x-8) 2 + (y - 6) 2 = 25

O B. (x+8) 2 + (y + 6) 2 = 5

O C. (x+8) 2 + (y + 6) 2 = 25

O D. (-8) 2 + (-6) 2 = 5

Question

Rachael Lawson

Mathematics

4 August, 13:59

What is the equation of a circle with center (8,6) and radius 5?

O A. (x-8) 2 + (y - 6) 2 = 25

O B. (x+8) 2 + (y + 6) 2 = 5

O C. (x+8) 2 + (y + 6) 2 = 25

O D. (-8) 2 + (-6) 2 = 5

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Answers (1)

Know the Answer?

Savion Frazier · Answer 1

A. (x-8) ^2 + (y - 6) ^2 = 25

Step-by-step explanation:

The formula for calculating the equation of a circle is (x-a) ^2 + (y - b) ^2 = r^2

substituting the values of a=8, b=6, and r=5

The equation of the circle becomes (x-8) ^2 + (y - 6) ^2 = 25

What is the equation of a circle with center (8,6) and radius 5?O A. (x-8) 2 + (y - 6) 2 = 25O B. (x+8) 2 + (y + 6) 2 = 5O C. (x+8) 2 + (y + 6) 2 = 25O D. (-8) 2 + (-6) 2 = 5

What is the equation of a circle with center (8,6) and radius 5?

O A. (x-8) 2 + (y - 6) 2 = 25

O B. (x+8) 2 + (y + 6) 2 = 5

O C. (x+8) 2 + (y + 6) 2 = 25

O D. (-8) 2 + (-6) 2 = 5