14 December, 00:41
The first side of a triangle is 8m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side
14 December, 01:07
Call the length of the second side ' S '.
(It could have any name. I just felt like calling it ' S ' for 'second'.)
The first side is 8m shorter = S - 8.
The third side is 4 times as long as the first side = 4 (S - 8).
When you add up all three sides, you have
(S - 8) + (S) + 4 (S - 8).
That's a mess.
We need to clean it up.
Eliminate the parentheses: S - 8 + S + 4S - 32.
Add up all the S's: 6S - 8 - 32
Add up all the plain numbers: 6S - 40.
That's the sum of all the sides.
Another name for it is 'perimeter'.
The question says it's 26m.
So we can write 6S - 40 = 26
Add 40 to each side: 6S = 66
Divide each side by 6 : S = 11 m
First side = S - 8 = 3 m
Second side = S = 11 m
Third side = 4 (S-8) = 12 m
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» The first side of a triangle is 8m shorter than the second side. The third side is 4 times as long as the first side. The perimeter is 26 m. Find the length of each side