Ask Question
29 January, 01:17

An artist drew a rectangle. the artist then modified the rectangle so thatthe length ofthe rectawngle increased by 30 percent and the width of the rectangle decreased by 40 percent. after the modification, what was the percent decrease in the area of the rectangle?

+4
Answers (1)
  1. 29 January, 01:47
    0
    The dimensions of the original rectangle

    length - L

    width - W

    area = L*W = LW

    after the modification, new dimensions are

    length increased by 30 %

    Length = L * 1.3 = 1.3L

    Width = W * 0.6 = 0.6W

    new area = 1.3L * 0.6W

    = 0.78LW

    the percent decrease in area

    decrease % = (difference in area) / original area * 100

    = (LW - 0.78LW) / LW * 100

    = 0.22LW/LW * 100

    = 22%

    percent decrease is 22%
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An artist drew a rectangle. the artist then modified the rectangle so thatthe length ofthe rectawngle increased by 30 percent and the width ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers