What is the probability that, after making two rolls with a fair (six-sided) die, you find that one or both of the rolls is greater than or equal to 4?

Question

Tripp Simpson

Mathematics

12 January, 00:24

What is the probability that, after making two rolls with a fair (six-sided) die, you find that one or both of the rolls is greater than or equal to 4?

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Skyler Randall · Answer 1

There are 36 total possibilities when one rolls a six sided die.

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6).

Out of these possibilities there are 3 that make 4.4 that make make 5. 5 that make 6. 6 that make 7. 5 that make 8. 4 that make 9. 3 that make 10. 2 that make 11 and 1 that makes 12. Now add the combinations 3+4+5+6+5+4+3+2+1. The answer would be 33.