A team member played 5 3/4 minutes during the first period, 2 2/3 minutes during the secound period, and 10 1/6 minutes during the third period. how many minutes did she play at all

Question

Cameron Mayer

Mathematics

4 March, 12:59

A team member played 5 3/4 minutes during the first period, 2 2/3 minutes during the secound period, and 10 1/6 minutes during the third period. how many minutes did she play at all

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Darcy · Answer 1

Well, it says "How many minutes did she play at all." So, we are going to add. First, we make 5 3/4 and 2 2/3 a improper fraction. 5 3/4=23/4 and 2 2/3=8/3. 23*3+8*4/4*3=69+32/12=101/12. 101/12 as a mixed number is 8 5/12. Now, we add 8 5/12 by 10 1/6. 8 5/12 as a improper fraction is 101/12 and 8 5/12 as a improper fraction is 61/6. 101*6+61*12/12*6=606+732/72=1,338/12. 1,338/12 simplified is 223/12. 223/12 as a mixed number is 18 7/12. Therefore, She played 18 7/12 minutes.