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Haleigh Estes
Mathematics
9 August, 02:11
What's the perimeter of 80 and115l
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Derick Barton
9 August, 02:23
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P=2 (l+w)
P = 2 (80 + 1151)
P = 2 (1231)
P = 2462
The given known values are: Length of 4 cm Width is unknown Perimeter is 34 cm Find the dimensions of the rectangle. Since the geometric formula for perimeter is:
P = 2 (l + w)
L = 2w - 4 cm
W = ?
Derivation and solution:
34 = 2 (2w - 4) + 2w
34 = 4w - 8 + 2w
42 = 6w 42/6 = w
W = 7 cm
34 = 2l + 2 (7)
34 = 2l + 14
2l = 34 - 14
2l = 20
L = 20/2
L = 10 cm
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