Given the function f (x) = x^3+x^2-2x+1, what is resulting when f (x) is shifted to the left 1 unit?

When the function is asked to be shifted to 1 unit to the left, we replace x with x + 1. Hence, f (x) = x3 + 2x2 - 2x + 1; f (x + 1) = (x + 1) ^3 + (x + 1) ^2 - 2 (x + 1) - 5

= (x^3 + 3x^2 + 3x + 1) + (x^2 + 2x + 1) - 2 (x + 1) + 1 = x^3 + 3x^2 + x^2 + 3x + 2x - 2x + 1 + 1 - 2 + 1 = x^3 + 4x^2 + 3x + 1

The final equation is x^3 + 4x^2 + 3x + 1